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3x^2+12=10
We move all terms to the left:
3x^2+12-(10)=0
We add all the numbers together, and all the variables
3x^2+2=0
a = 3; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·3·2
Δ = -24
Delta is less than zero, so there is no solution for the equation
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